Question

Help writing equations using point-slope form?... find the slope and standard form of the line that passes through the points (3,6) and (4,5) help!

Answer 1

slope = (y2-y1)/(x2-x1)
then use Point-slope form

Answer 2

x2 is not x^2.......

Answer 3

slope between two points is \[m=\frac{ \Delta y }{ \Delta x }\]
point slope form: \[y-y _{1} = m (x-x _{1})\]

Answer 4

One sec..

Answer 5

Can you explain it better please?

Answer 6

Like how to plug it in and everything.

Answer 7

\[m=\frac{ \Delta y }{ \Delta x } = \frac{ y _{1} - y _{2} }{ x _{1} - x _{2} }\]
from your points (3,6) and (4,5). Choose one to be point 1 and point 2 (it doesn't matter which one you choose to be which)
\[P _{1} = (x _{1},y _{1}), P _{2} = (x _{2},y _{2})\] then plug the point into the equation above.

Answer 8

I STILL DONT GET IT

Answer 9

and im getting all of the answers wrong

Answer 10

let's say \[P _{1}=(3,6), P_2=(4,5)\] plugging this in we get
\[m=\frac{ \Delta y }{ \Delta x } = \frac{ y _{1} - y _{2} }{ x _{1} - x _{2} }= \frac{ 6-5 }{ 3-4 } = \frac{ 1 }{ -1 }=-1\]
then plugging that into the equation for y
\[y-y _{1} = m (x-x _{1})\]
\[y-6 = -1 (x-3)\]

Answer 11

you must be wrong because your answer isnt in the choices :|

Answer 12

@xon1300

Answer 13

the choices all start with m

Answer 14

slope m = -1, \[y= -x +9\] or \[x+y=9\]