Question

prove the identity: (sec^2 theda)(csc^2theda) = (csc^2theda) + (sec^2theda) PLEASE HELP!

Answer 1

the picture is cut off

Answer 2

the answer is sec^2 x + csc^2 x, can u see it?

Answer 3

I can see part of the answer

Answer 4

tan^2 x +1 = sec^2 x
1 +cot^2 x = csc^2 x
so, (sec^2x)(csc^2 x) =(tan^2 x +1) (1+ cot^2 x) = tan^2 x + (tan^2 x)(cot^2 x) +1 + cot^2 x
= tan^2 x + 1 + 1 + cot^2 x = sec^2 x + csc^2 [(tan^2 x)(cot^2 x) = 1]

Answer 5

thank you! I understand your steps. can you maybe help me with another one?

Answer 6

no problem