Question

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

equation in comments

Answer 1

\[y= \int\limits_{sinx}^{cosx} (1+v^6)^7 dv\]

Answer 2

chain rule plus ft of c

Answer 3

replace \(v\) by \(\cos(x)\) then multiply by the derivative of \(\cos(x)\) you get
\[-(1+\cos^6(x))^7\sin(x)\]

Answer 4

then repeat with \(\sin(x)\) but this time subtract

Answer 5

i get \[-\sin x(1+\cos^6x)^7-\cos x(1+\sin^6x)^7\]

Answer 6

me too

Answer 7

thanks a lot

Answer 8

yw