Question

Two moles of an ideal gas are placed in a container whose volume is 8.2 10-3 m3. The absolute pressure of the gas is 2.7 105 Pa. What is the average translational kinetic energy of a molecule of the gas?

Answer 1

Check the units of Boltzmann's constant and that should be a clue.

Answer 2

u know translational kinetic energy of 1 mole is\[E=\frac{ 3 }{ 2 }RT\]

Answer 3

here R=boltzman constant
T=temperature in kelvin scale

Answer 4

R=8.31

Answer 5

T=?

Answer 6

given that n=2
vollume \[V=8.2 \times 10^{-3} m ^{3}\]

Answer 7

pressure \[P=2.7105 pa\]

Answer 8

anyway mole nomber =n=2 mole

Answer 9

now we know that \[PV=nRT\]

Answer 10

\[or, T=\frac{ PV }{ nR }\]

Answer 11

i think u will b able to solve it now. if u need any explanation plz ask me