Question

dy/dx of

Answer 1

dy/dx of what..?

Answer 2

\[e^{2x}=\sin(x+3y)\]

Answer 3

@bballin629

Answer 4

sorry mate, I don't know how to do e^2x but sin(x+3y) would probably be the chain rule

Answer 5

@hartnn

Answer 6

i was using the rule of sin (a+b) but it be more compilcated..

Answer 7

@jim_thompson5910 ,@amistre64

Answer 8

use implicit derivative for right side

Answer 9

howis it.. i still can get you..

Answer 10

well , i want to show u how implicit's derivative will work
e^(2x) = sin(x+3y)
2*e^(2x) dx = sin(x+3y) dx + sin(x+3y)*3dy
sin(x+3y)*3dy = 2*e^(2x) dx - sin(x+3y) dx
3sin(x+3y)dy = (2*e^(2x) - sin(x+3y)) dx
dy/dx = (2*e^(2x) - sin(x+3y))/3sin(x+3y)

Answer 11

opppss... my mistake not change sin to cos :)
it should be :
2*e^(2x) dx = cos(x+3y) dx + cos(x+3y)*3dy or
cos(x+3y)*3dy = 2*e^(2x) dx - cos(x+3y) dx
3cos(x+3y)dy = (2*e^(2x) - cos(x+3y)) dx
dy/dx = (2*e^(2x) - cos(x+3y))/3cos(x+3y)

Answer 12

so when we know which method we need to used..

Answer 13

actually, if there are two variables (x and y)
so use by implicit's derivative