Question

(1) Write log9+1/3log729 as a single logarithm.

(2) Write log[2]5-1/2log[2]169 as a single logarithm.

Answer 1

1) the 1/3 would just be the exponent of log(729) so log(729)^1/3 and then we use log rule log(ab)= log(a)+log(b) to get log(9)(729)^(1/3)

Answer 2

log(6561)^(1/3)

Answer 3

so i solve that? @jbovey i got In9/in10

Answer 4

is that for the #(2)?

Answer 5

no thats the answer for #1. Since it says just write as single log you wouldn't have to solve any further

Answer 6

it just wants you to use the log rules and combine

Answer 7

oooh ok.. so what about #2?

Answer 8

Im kind of confused by the way you wrote it. Can u draw the equation out so I can see?

Answer 9

yupp! hold on..

Answer 10

I know you'll have to use log rule 3 which is log(a)-log(b)= log(a)/(b)