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(1) Write log9+1/3log729 as a single logarithm. (2) Write log[2]5-1/2log[2]169 as a single logarithm.
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1) the 1/3 would just be the exponent of log(729) so log(729)^1/3 and then we use log rule log(ab)= log(a)+log(b) to get log(9)(729)^(1/3)
log(6561)^(1/3)
so i solve that? @jbovey i got In9/in10
is that for the #(2)?
no thats the answer for #1. Since it says just write as single log you wouldn't have to solve any further
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it just wants you to use the log rules and combine
oooh ok.. so what about #2?
Im kind of confused by the way you wrote it. Can u draw the equation out so I can see?
yupp! hold on..
I know you'll have to use log rule 3 which is log(a)-log(b)= log(a)/(b)
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