Question

Please help!
Solve the system of equations using matrices. Use Gaussian elimination with back-substitution.

3x + 5y - 2w = -13
2x + 7z - w = -1
4y + 3z + 3w = 1
-x + 2y + 4z = -5

Answer 1

[ 3 5 0 -2 -13 ]
[ 2 0 7 -1 -1 ]
[ 0 4 3 3 1 ]
[ -1 2 4 0 -5 ] can you continue next ?

Answer 2

gaussian is to make it like

Answer 3

@alyssababy7 can you follow and do the next steps? .:D
let me know.... :D

Answer 4

A. {(-1, -(20/3), 0, 2/5)}
B. {(1, -2, 0, 3)}
C. {(3/4, -2, 0, 3/4)}
D. {(4/3, -(13/20) , 0, 5/2)}
My options

Answer 5

did you try solving that yet? after back substitution what did you get for x,y,z and w?

Answer 6

i did this this way,
from
[ 3 5 0 -2 -13 ]
[ 2 0 7 -1 -1 ]
[ 0 4 3 3 1 ]
[ -1 2 4 0 -5 ]

[ -1 2 4 0 -5 ] mult by -1--> [ 1 -2 -4 0 5 ]
[ 0 4 3 3 1 ] [ 0 4 3 3 1 ]
[ 2 0 7 -1 -1 ] [ 2 0 7 -1 -1 ]
[ 3 5 0 -2 -13 ] [ 3 5 0 -2 -13 ]

now its easy to manipulate them to be echelon form

Answer 7

I just don't understand this.

Answer 8

[ 1 -2 -4 0 5 ]
[ 0 4 3 3 1 ]
[ 2 0 7 -1 -1 ]
[ 3 5 0 -2 -13 ]


try to continue this one tobe gaussian echelon form