Question

Evaluate Intregral.

Answer 1

\[\int\limits_{0}^{1} (6x dx) / (\sqrt{16+3x^2})\]

Answer 2

i have all the way to du/ sqrt(u)

Answer 3

\[\int\limits_{0}^{1}\frac{ du }{ \sqrt{u} }\]

Answer 4

well, then use the \(\int u^n du = \frac{u^{n+1}}{n+1}+C\), where n=1/2

Answer 5

sorry, n=-1/2

Answer 6

thank you!

Answer 7

you're welcome :)