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Mathematics 17 Online
OpenStudy (anonymous):

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OpenStudy (australopithecus):

Well for the asymptotes look at the unit circle might help to memorize it remember the identity tan(x) = sin(x)/cos(x) so you will have an asymptote everytime cos(x) = 0, because you cannot divide by zero tan(4x) = sin(4x)/cos(4x) these asymptotes will continue infinitely so you have to denote that in your answer

OpenStudy (australopithecus):

You will have vertical asymptotes as you approach where cos(x) = 0 this will also tell you what your domain is

OpenStudy (australopithecus):

as for range of tan(x), look at the graph of the function and memorize it. It helps to know it. from the graph of tan(x) you can see what the range of tan(4x) is.

OpenStudy (anonymous):

okay thank you! Do you know how to find the period?

OpenStudy (australopithecus):

as for period all you do is divide 2pi by the multiple or divider of x or theta in the function. so if you had sin(3x) to find the period 2pi/3x to find the period of sin(x/4) 2pi/(1/4) = 2pi(4/1) = 2pi(4)

OpenStudy (australopithecus):

But yeah if you plan on taking calculus in university memorize these trig graphs and if you feel like you want to be super prepared you can memorize the unit circle but there are other better ways to remember it apparently

OpenStudy (australopithecus):

made a mistake to find the period sin(3x) 2pi/3

OpenStudy (australopithecus):

it is pretty simple hope you follow

OpenStudy (australopithecus):

follow?

OpenStudy (anonymous):

so would the domain be all real numbers except npi/8 where n is odd range all real numbers and asymptotes pi/8 +- n4/pi?

OpenStudy (australopithecus):

well you only have to denote two asymptotes for this function, so dont worry about showing then repeated, range =all real numbers like you said as for domain it would be the period +/- npi , where n = an integer

OpenStudy (anonymous):

what would the period be again? +/- npi?

OpenStudy (australopithecus):

I showed you how to figure out period

OpenStudy (anonymous):

would it be 2pi/3x?

OpenStudy (australopithecus):

ugh no, just divide 2pi by the multiple or divider of x in the trig function so sin(3x) would have the period 2pi/3 cos(x/3) would have the period 2pi/(1/3) etc

OpenStudy (anonymous):

alright thank you

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