Will someone please help me with the process of how to do this?... If 4000 dollars is invested in a bank account at an interest rate of 5 per cent per year, find the amount in the bank after 12 years if interest is compounded annually, quarterly, monthly, and continuously
For compound interest:\[A = P \times (1 + \frac{ r }{ t })^{yt}\]where r is the APR, t is the number of compounding periods per year, and y is the number of years. For compounding continuously,\[A = P \times e ^{ry}\]
So, the easiest one is for compounding annually:\[A = 4000 \times (1 + 0.05)^{12}\]
Awesome! I just worked it out and got it right on my homework. Thank you!
Quarterly:\[A = 4000 \times (1 + \frac{ 0.05 }{ 4 })^{(4)(12)}\]
Thanks!
I'll let you use quarterly as a model to figure the monthly problem. As for continuously:\[A = 4000 \times e ^{(0.05)(12)}\]
uw!
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