how do u find the electron configuration of a chloride ion?
what configuration does the Chlorine atoms have in it's neutral state
atom*
no, how many electrons does a chlorine atom have?
17?
yep, so you know it's in group 7, and it has 7 valence electrons. you know that they want to achieve a valence electron count of 8 (because of its stability), so is it easier for the chlorine atom, that has 7 valence electrons, to gain 1 electron, or to lose 7 electrons, to have an "octet"?
whats an "octet"?
it's a name given to a valence electron count of 8, which is what atoms seek to achieve.
just a quick check for me.. an atom and element are the same? pretty much?
an element is species defined by a specific amount of protons, an atom is a particle composed of protons, neutrons, and electrons. so their definitions are different, but they can be used interchangeably
ok now back to the original question.. where were we?
so is it easier for the chlorine atom, that has 7 valence electrons, to gain 1 electron, or to lose 7 electrons, to have an "octet"?
to gain 1
okay, now just add one electron to the electron configuration of the neutral atom. (it should look like the nearest noble gas's config)
Argon?
yep
so there are 8 electrons on an chloride ion?
in*
8 valence (outermost) electrons, yes. the answer is \[1s^{2}2s^{2}2p^{6}3s ^{2}3p ^{6}\] btw
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