Question

Factor the polynomial completely:
9n^3-36n
Thought this one would be easy and it probably is but i cant figure it out. Help.?

Answer 1

There is a common factor in \[9n^3-36n\]The common factor is \[9n\]

Answer 2

When you pull the common factor out you get
\[9n(n^2-4)\] However, this is still factorable.

Answer 3

\[(n^2-4)\] is the same as \[(n-2)(n+2)\] so the total factorization comes out to be \[9n(n-2)(n+2)\] If you multiply everything out and distribute through to check your work, you'll end up with the original problem.

Answer 4

Thank you. I see what i was doin wrong now. I appreciate the help.

Answer 5

You're very welcome.