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Factor the polynomial completely: 9n^3-36n Thought this one would be easy and it probably is but i cant figure it out. Help.?
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There is a common factor in \[9n^3-36n\]The common factor is \[9n\]
When you pull the common factor out you get \[9n(n^2-4)\] However, this is still factorable.
\[(n^2-4)\] is the same as \[(n-2)(n+2)\] so the total factorization comes out to be \[9n(n-2)(n+2)\] If you multiply everything out and distribute through to check your work, you'll end up with the original problem.
Thank you. I see what i was doin wrong now. I appreciate the help.
You're very welcome.
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