can someone remind me how to do these: 125=5^x
wolframalpha.com walks you through it
ok, what are they even called? I didn't know how to search for it
just put your equation in
I'll just teach you...
You have to take the log or natural log (ln) of both sides
\[\log 125 = \log 5^x\]
This is equal to \[\log 125 = x \log 5\]
I think it's just common sense. 5x5=25 25x5 = 125 therefore 5x5x5=125 therefore 5^3 = 125 therefore X=3
the exponent can be brought out in front.
@Anna1998 x is in the power not multiply with 5
@ChmE when I do log of 125 I get 2.0969
@brandonloves not finished yet
shutting up :-)
now to get x by itself we divide both sides by log 5\[\frac{ \log 125 }{ \log 5 }=x\]
3!
\[125=5^x\]\[\log 125 = \log 5^x\]\[\log 125 = x \log 5\]\[\frac{ \log 125 }{ \log 5 }=x\]
seems like I remember doing them another way that was pretty easy... what if it was 16^x=28 .83?
oh, maybe we just guessed them...
|dw:1354598241250:dw| this is how we worked them in class, but that was a couple months ago, and I forgot what it all means @ChmE
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