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Mathematics 19 Online
OpenStudy (anonymous):

question attached inside :)

OpenStudy (anonymous):

question!! :) **no answer choices!! idk how to do this one :(

OpenStudy (anonymous):

I'm still confused how to do that :( like how do i simplify it into that format?

OpenStudy (anonymous):

how do i find k? i don't understand.. how can i see it right off the bat?

OpenStudy (anonymous):

Ok I'll teach you how to complete the square very easily.

OpenStudy (anonymous):

okay :) thanks!!

OpenStudy (anonymous):

\[y^2-2y-11\]take half the middle term which is -1\[(y-1)^2\]Now we have to take out what we just added. We added -1^2 so we need to take out 1\[(y-1)^2-1\]We can see that when we expand this back out we would have y^2-2y+1-1 so we are left with y^2-2y. The last thing we can't forget it the -11 at the end.\[(y-1)^2-1-11=(y-1)^2-12\]

OpenStudy (anonymous):

To check when we expand this we get the original equation

OpenStudy (anonymous):

Now to relate this to this problem

OpenStudy (anonymous):

ohhh i see :) so hmmm idk if i am right... is my answer k=1 then? idk is that right?? is the value of k, 1?

OpenStudy (anonymous):

\[x^2+(y-1)^2-12=0 \rightarrow x^2+(y-1)^2=12\]So now can you see what k is?

OpenStudy (anonymous):

is k=1 ?

OpenStudy (anonymous):

idk is that right? :O

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

Did you understand how to complete the square?

OpenStudy (anonymous):

yup :) thanks so much1! :) that explanation was great :)

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

thank you!! :D

OpenStudy (anonymous):

yw

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