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OpenStudy (anonymous):
question!! :)
**no answer choices!!
idk how to do this one :(
OpenStudy (anonymous):
I'm still confused how to do that :( like how do i simplify it into that format?
OpenStudy (anonymous):
how do i find k? i don't understand.. how can i see it right off the bat?
OpenStudy (anonymous):
Ok I'll teach you how to complete the square very easily.
OpenStudy (anonymous):
okay :) thanks!!
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OpenStudy (anonymous):
\[y^2-2y-11\]take half the middle term which is -1\[(y-1)^2\]Now we have to take out what we just added. We added -1^2 so we need to take out 1\[(y-1)^2-1\]We can see that when we expand this back out we would have y^2-2y+1-1 so we are left with y^2-2y. The last thing we can't forget it the -11 at the end.\[(y-1)^2-1-11=(y-1)^2-12\]
OpenStudy (anonymous):
To check when we expand this we get the original equation
OpenStudy (anonymous):
Now to relate this to this problem
OpenStudy (anonymous):
ohhh i see :) so hmmm idk if i am right... is my answer k=1 then? idk is that right?? is the value of k, 1?
OpenStudy (anonymous):
\[x^2+(y-1)^2-12=0 \rightarrow x^2+(y-1)^2=12\]So now can you see what k is?
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OpenStudy (anonymous):
is k=1 ?
OpenStudy (anonymous):
idk is that right? :O
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
Did you understand how to complete the square?
OpenStudy (anonymous):
yup :) thanks so much1! :) that explanation was great :)
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