can someone help me with a trig equation again?

Question

anonymous · Answer

anymore clue?

anonymous · Answer

$$3\sqrt{2}\cos \theta+2=-1$$

anonymous · Answer

interval is 0 to pi

nubeer · Answer

first subtract 2 on both sides.. 
then divide the whole equation by 3

anonymous · Answer

oh i get it now, thank you

anonymous · Answer

can you also help me with writing the answer?
since it has an infinite amount of answers

nubeer · Answer

hmm as a matter it dont have infinit answers it has range 0-pi.. well have you found the value of theta?

anonymous · Answer

subtract 2 on both sides and get
3sqrt(2)cos(theta) = -3
divide 3sqrt(2) on both sides and get 

cos(theta) = 1/sqrt(2)
rationalize the denominator

cos(theta) = sqrt(2)/2
since its from 0 to pi you will and cost = sqrt(2)/2 at pi/4
so your answer is pi/4

anonymous · Answer

if i divide both sides by three is it $$\sqrt{2}/3\cos \theta=-1$$

nubeer · Answer

hmm no.. well you can look at @jayz657  comment , most of the solution is written.

nubeer · Answer

@jayz657  you missed the "-" somewhere.

anonymous · Answer

oh i divided only the 3, i didnt know you were suppose to divide 3and the sqrt2

anonymous · Answer

thank you

anonymous · Answer

can you help me with how i would write it if there was no interval?

anonymous · Answer

oh sorry it should be - sqrt(2)/2
so it will be 3pi/4 instead