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Mathematics 17 Online
OpenStudy (mayankdevnani):

urgent!!!!

OpenStudy (mayankdevnani):

If \[\sqrt{6}=2.449\] then the value of \[\frac{3\sqrt{2}}{2\sqrt{3}}\] is close to

OpenStudy (binary3i):

2.449/2

OpenStudy (unklerhaukus):

time the numerator and denominator by \sqrt 2

OpenStudy (mayankdevnani):

options- a)1.225 b)0.816 c)0.613 d)2.449

OpenStudy (binary3i):

1.2245

OpenStudy (mayankdevnani):

howz that? @binary3i

OpenStudy (binary3i):

\[[3 \sqrt{2}]/[2 \sqrt{3}] = [\sqrt{3} \sqrt{2}]/2=\sqrt{6}/2 \]

OpenStudy (mayankdevnani):

i don't understand..plz draw it

OpenStudy (unklerhaukus):

\[\frac{3\sqrt{2}}{2\sqrt{3}}=\frac{3\sqrt{2}}{2\sqrt{3}}\times\frac11\]\[\qquad\qquad=\frac{3\sqrt 2}{2\sqrt{3}}\times\frac{\sqrt2}{\sqrt2}\]\[\qquad\qquad=\frac{3\times2}{2\sqrt{6}}\]\[\qquad\qquad=\frac{3}{\sqrt{6}}\]\[\qquad\qquad\approx\frac{3}{2.5}\]\[\qquad\qquad=\frac{12}{10}\]\[\qquad\qquad=1.2\]

OpenStudy (mayankdevnani):

how did you get 12/10 @UnkleRhaukus

OpenStudy (unklerhaukus):

\[\frac{3}{2.5}=\frac3{2.5}\times\frac{1}{1}\]\[\qquad=\frac3{2.5}\times\frac{4}{4}\]\[\qquad=\frac{12}{10}\]

OpenStudy (mayankdevnani):

oh!!! i got it !! thank you very much @UnkleRhaukus and @binary3i

OpenStudy (sirm3d):

@binary3i 's solution is the superior solution.

OpenStudy (binary3i):

it depends on the solution you understand

OpenStudy (sirm3d):

\[\large \frac{ 3\sqrt2 }{ 2\sqrt3 }\frac{ \sqrt3 }{ \sqrt3 }=\frac{ 3\sqrt 6 }{ 2(3) }=\frac{ \sqrt 6 }{ 2 }=\frac{2.449}{2}\]

OpenStudy (mayankdevnani):

ohkk thnx.. @sirm3d

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