Question

help~
solving this for lambda1 and lamba2:
2+(lambda1)(2x)+(lambda2)=0
2+(lambda1)(2y)+(lambda2)=0
2z+(lambda1)(2z)+(lambda2)=0

Answer 1

\(2+(\lambda_1)(2x)+(\lambda_2)=0\)
\(2+(\lambda_1)(2y)+(\lambda_2)=0\)
\(2z+(\lambda_1)(2z)+(\lambda_2)=0\)
are you supposed to solve it in terms of x,y ,z?

Answer 2

wow thank you I was just typing the equations out again.

No the answer should be a number.

and x+y+z=3

Answer 3

and \[x ^{2} + y^{2} + z^{2} = 11\]
I don't know if these have to be used...

Answer 4

you're welcome :)
oh gosh. lol these should help out a lot.

Answer 5

does the third eq really have that 2z infront there?

Answer 6

yes

Answer 7

may I ask.. can the lagrange multiplier be zero?

Answer 8

they might? I'm not really sure.
I've got (-1,1,3)for (x,y,z) if they are integers...but this isn't much help, is it?

Answer 9

think I got it, thanks

Answer 10

you're welcome :)