Question

Convert the equation to the standard form for a hyperbola by completing the square on x and y.
y^2 - 25x^2 + 4y + 50x - 46 = 0

Answer 1

lol another multiple choice?

Answer 2

Yes
A. (x+2)^2/25 - (y-1)^2 = 1
B. (x-1)^2 - (x+2)^2/25 = 1
C. (x+2)^2/25 - (x-1)^2 = 1

Answer 3

ok well that makes it much easier

Answer 4

actually there must be something wrong here, because the \(y^2\) term comes first

Answer 5

\[y^2 - 25x^2 + 4y + 50x - 46 = 0
\]

Answer 6

these are my only options :/

Answer 7

if the last one is really \[\frac{(y+2)^2}{25}-(x-1)^2=1\] then go with that one

Answer 8

thank you, i'm going to go with it.