log(2x-1) + log5 = 1

Question

nubeer · Answer

log (5(2x-1)) =1
log has base 10.. take it on the other side
$$5(2x-1) = 10^{1}$$

anonymous · Answer

Thanks!  What about ln(x-1) + ln6 = ln(3x)

nubeer · Answer

when two logs are added they are being multiplied.. and when two logs are being subtracted they are divided..
in this one multiply 6 with x-1 making one ln on each side... whenever there is 1 ln on both sided u can cancel them

anonymous · Answer

so it's the same as log?  [6(x-1)] = 3x ?

nubeer · Answer

yes same as log.. and yes it's right.

anonymous · Answer

the is 1/3 ?

nubeer · Answer

hmm no..6x-6=3x
try to solve now..

anonymous · Answer

6x-6=3x,  3x = 6,  x=6/3  x=2       that was a dumb moment!  Thanks!!

anonymous · Answer

in f(x) =(x^3 - 3x^2 + 6) / (x+2)  my answer is x^2-5x+10- (14/x+2)   did I do this correctly?

nubeer · Answer

lol well u can try wolfram if you just want to check answers.. , but ya i think u did it right.

anonymous · Answer

Yeah, They give me the answer but sometimes I get the answer correct but not the steps.  I'm just trying to be sure I have the procedure correct for finals on Thursday.  Thanks for your help!!

nubeer · Answer

no problem at all. you are most welcome.