Question

Determine the area under the standard normal curve that lies to the left of the following z value:

z = –0.33

Use a table if necessary. Round your answer to the nearest ten thousandth.

Answer 1

Please help me... :(

Answer 2

what do you have to use? calculator, program, table, etc ...

Answer 3

integrating the function?

Answer 4

\[\Large \frac{1}{\sigma\sqrt{2\pi}}~\int_{a}^{b}e^{\frac{(x-\mu)^2}{2\sigma^2}}dx\]

and since a normal curve without any other information is assumed to have a u=0 and sd=1

\[\Large \frac{1}{\sqrt{2\pi}}~\int_{a}^{b}e^{\frac{x^2}{2}}dx\]

Answer 5

can you go through the steps? Sorry, but I am so confused

Answer 6

I don't have a calculator, program or table :(

Answer 7

i need to know what you have to do this with; ideally a table or a ti83

Answer 8

we need to find it on a table I believe

Answer 9

hmm, a table can be found online, goole ztable

Answer 10

http://statstutorstl.blogspot.com/2010/07/z-table-gives-probabilty-distribution.html

heres one thatll do fine

Answer 11

0.3707?

Answer 12

maybe, how did you get to that?

Answer 13

I went to -0.33 and used the number provided

Answer 14

there was a -0.33 ?

onthe table i linked to; they measure from the mean; so if we cross hairs 0.3 with .03 we get .6293, which is .5000 to big

Answer 15

you use both the colum on top and on the side

Answer 16

yes

Answer 17

I didn't use the table you posted

Answer 18

which table did you use?

Answer 19

you didn't look on the negative portion of the chart

Answer 20

heres another question
Determine the area under the standard normal curve that lies to the left of the following z score. Use a table if necessary. Round your answer to four decimal places.

z = 0.33

Answer 21

ah, i see my error;