Question

How many ordered triples of positive intergers satisfy the equation a+b+c=6

Answer 1

eksploration problem
case I :
for a=1, so b+c=5 or c=5-b
c will be an integer positive, if b=1,2,3, and 4
so, the total way = 4 ways
case II :
for a=2, so b+c=4 or c=4-b
c will be an integer positive, if b=1,2, and 3
so, the total way = 3 ways
case III :
for a=3, so b+c=3 or c=3-b
c will be an integer positive, if b=1, and 2
so, the total way = 2 ways
case 1V :
for a=4, so b+c=2 or c=2-b
c will be an integer positive, if b=1
so, the total way = 1 ways
the total way from all cases = 4+3+2+1 = 10