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Can you show me step by step how to solve this using Laplace?
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\[f(t)=\sqrt{t}+3t\]
Not much to the steps. Go to the Laplace transforms table and look them up. Laplace transform of root of t is: \[\sqrt{t} = \frac{ \sqrt{\pi}}{2s^{\frac{3}{2} }}\] Laplace transform of t to the n power: \[t^{n}=\frac{n!}{s^{n+1}}\] so \[3t=3\frac{1}{s^2}\]
How did you get sqrt(pi) @Rudy ?
I looked it up on the table. That's how it's listed. Are you solving using the definition of a Laplace transform?
I think I am supposed to, I don't see that on my table.
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