Question

3^2x derivative

Answer 1

2.3^(2x) ln3

Answer 2

is it 2.3 ?

Answer 3

\[2(3^{2x}) \ln 3\]

Answer 4

ok got it

Answer 5

need details?

Answer 6

actually yes

Answer 7

ok then, so that type of derivetive is a^(u(x)) where "a" is a constant and "u(x)" is the equation, derived i looks like" u(x)' a^(u(x)) ln a", it looks complicated i know :P

Answer 8

got it ` thank you

Answer 9

oh and you have to finish by multipling 2 by 3 so final answer is \[6^{2x}\ln 3\]

Answer 10

use the squeeze theorem to show that if 0le f(x) le 5 , for all x in [ 0 , 1], then lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0

Answer 11

0le f(x) le 5

Answer 12

\[use the squeeze theorem \to show that if 0\le f(x) \le 5 , for all x \in [ 0 , 1], then \lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0\]

Answer 13

0le f(x) le 5 , for all x in [ 0 , 1],

Answer 14

sorry but i cant help you, i've never used the theorem before

Answer 15

does it say what f(x) is ?

Answer 16

no

Answer 17

lim_{x rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0

Answer 18

\[\lim_{x \rightarrow 0^+} \ \left( e^{x} - 1\right) f(x) =0 \]