Find angle theta if the cos is 4/7 and the sin is negative. Please explain in detail if you can!
In which quadrants is sin negative? That's the first thing you need to think about.
Sin is negative in the III and IV quadrants.
So you know it has to be in one of those two quadrants. Out of those 2, which one is cos positive?
Uh, IV
Correct. Now, \[\cos^-1(4/7)=\theta\]
55.15009542
thats cos^-1(4/7)=theta.
That will give you your reference angle. From there, what do you have to do to find what that angle is in the fourth quadrant?
That is where I am lost
Well, the first quadrant is 0-90 degrees. The second 91-180, third 181-270, fourth 271-360. So if you have an angle of 55, you,re in the first quadrant and you want to go to the fourth. So you want to reflect the angle over the x axis. The x axis can be 0 degrees or 360 degrees. So to move to the fourth, subtract your reference angle from 360.
AH! Thank you! That helps so much.
I remember this now. I forgot I learned it last year
No problem :] Trust me, I know how that feels.
I'm getting all my answers correct on my lesson now! Thank you again :)
You're very welcome. :]
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