Please help me with my homework i really dont know how to do these its algerbra please explain how to do these because i have slow mind so please explain each problem thanks 1. Estimate the slope of a line that is perpendicular to the line through (2.07,8.95) and (-1.9,25.07). 2. Explain in words how tp write an equation in slope-intercept form that describes a line parallel to y-3=-6(x-3).
slope = m, \[m=\frac{ y2-y1 }{ x2-x1 }\]
For part 1. (a) First find the slope of the line through the points you're given, and call it m. Then (b) the slope of the perpendicular line is -1/m
Use the formula that TaRJeel wrote to get the slope, m. Once you know m, do -1/m to get slope of perpendicular line.
its says to estimate
For part 2. First you need to get the given equation in slope-intercept form. To do that, you simply solve for y and write it as y = mx + b. After doing that, any line that has the same value of m and a different b is a parallel line.
explain that please cause i dont understand a thing you're saying
You still need to use the formula, but use approximations for the numbers: use (2,9) and (-2,25). Those two points are close to the ones you were given.
For part 1. To estimate the slope, you have approx (2,9) and (-2,25). Using the slope formula, that gives: m = (25 - 9)/(-2 - 2) = 16/(-4) = -4
ok let me do that hold up give me like 3 min
That means the line you have has a slope of approximately -4.
ok
ok i did that a got the same answer...so whats next
m = -4 is the approximate slope of the line you were given. The slope of a line perpendicular to a line of slope m is -1/m. In other words, if one line has slope m, and you want the slope of a perpendicular to it, the slope of the perpendicular is -1/m
-1/m means divide -1 by m and change the sign
im still confused im so sorry
You understood the slope of -4 right?
yes that was what i understand out of this
Ok the next step of part 1 is to find the slope of the perpendicular line. What you need to know is that the slopes of 2 perpendicular lines multiply to give you -1. That means that if you divide -1 by the slope of a line you get the slope of its perpendicular.
Since line you were given has slope -4, the slope of the perpendicular is -1/-4 (negative 1 divided by negative 4) and is -1/-4 = 1/4. So the slope of the perpendicular is 1/4
ok i think i get it
That takes care of part 1
ok then what do i do next
Now for part 2. An equation in slope-intercept form is an equation in the form: y = mx + b. Take the equation of part 2, and solve for y and write in the form y = mx + b: y - 3 = -6(x - 3) You want y alone on left side
First you must distribute the -6 on the right side: y - 3 = -6x + 18 Now you add 3 to both sides: y = -6x + 21 Now you have an equation with only y on the left side and the right side is in the form mx + b, where m = -6 and b = 21
The last step in part 2 is: A line parallel to the given line has equation y = -6x + b, where b is a number not 21
hold on please
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