Question

Given: In ∆ABC, segment DE is parallel to segment AC .
Prove: BD over BA equals BE over BC
The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.

Statement

Reason
1. segment DE is parallel to segment AC

1. Given
2. Line segment BA is a transversal that intersects two parallel lines

2. Conclusion from Statement 1
3.

3.
4. ∡B ≅ ∡B

4. Reflexive Property of Equality
5. ∆ABC ~ ∆DBE

5. Angle-Angle (AA) Similarity Postulate
6.

6.

Answer 1

Complete the proof by entering the correct statements and reasons.

Answer 2

@amistre64 @jim_thompson5910

Answer 3

@Hero

Answer 4

3. ∡BDE ≅ ∡BAC
3. Corresponding Angles Are Congruent

Answer 5

@Hero what about 6?

Answer 6

Bro, giving you that is like giving you the answer.

Answer 7

is 6 something along the lines of ABC~DBE because they're similar triangles?

Answer 8

I dont understand number 6

Answer 9

The last entry is always what you have to prove so

6. BD over BA equals BE over BC
6.

Answer 10

Good luck figuring out the reason