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lim as x-->(- pi/2)^-. Find lim sec x A) -infinity B) infinity C)0 D)1
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Please rewrite your question.
im thrown off my the (-pi/2)^- the negative is confusing me
I see. That is not a negative exponent. That means the x approaches -pi/2 from LEFT.
ohhhh that makes since. so wehre do i go from there
To tackle this kind of question, we first convert sec(x) to 1/cos(x).
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cos of pi/2 from the left gives -0.00000000000000000000000000000000000001 1/-0.00000000000000000000000000000000000001 = -infinity
Thank you.
Nooo problem :]
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