Question

1/n-8 - 1 = 7/n-8

Answer 1

@teyo212

Answer 2

cross multiply then solve for n.

Answer 3

how??

Answer 4

First of all @teyo212, you might want to use the drawing button, to write your question in a more appropriate form.

Answer 5

left side, common denominator. then cross multiply

Answer 6

Every time I say @teyo212, he disappears.

Answer 7

ok....im not gettin it

Answer 8

Bro, all you have to do is click the drawing button and write your math problem on it. How difficult is that?

Answer 9

I'm going to assume

\[\frac{1}{n-8} - 1 = \frac{7}{n-8}\]

Answer 10

\[\frac{1}{ n-8 } -\frac{ n- 8}{n-8} = \frac{7}{n-8 }\]
multiply by n-8 to cancel out the fractions, then solve.

Answer 11

If that's the case, simply multiply both sides by n - 8 to get

1 -(n - 8) = 7

Afterwards:
1 - n + 8 = 7
1 + 8 - n = 7
9 - n = 7
9 - 7 = n
2 = n

Answer 12

@jennychan12, you intercepted my explanation

Answer 13

multiply each term by n-8, then solve.
this is basic algebra...

Answer 14

@jennychan12, what is your math level?

Answer 15

calculus

Answer 16

Okay

Answer 17

sorry, this is like super easy for me compared to what i'm learning right now...
btw, @teyo212 what's ur answer if u ever solved it?

Answer 18

I'm much higher level than you

Answer 19

it doesn't matter.
calculus is calculus.
what r u in bc? cd?

Answer 20

I graduated from Calculus, lol

Answer 21

okay....
yet ur picture is i hate math...
interesting

Answer 22

Like someone else said, "I hate it because it is so easy"

Answer 23

use the upper and lower sums to approximate the area. y=x^1/2 +2
<--- it's there somewhere. help? please and thank you.

Answer 24

oh and whoops it goes from 0 to 2.

Answer 25

Is this a joke? I'm not going to even help you with that easy question. This is Calc I level, lol

Answer 26

i have an answer, i just want to check if it's right.

Answer 27

I have confidence in your abilities. That, and I'm not really interested in helping with that particular question.