Trigonometry
22 Online
OpenStudy (anonymous):
Help? D: How do you determine the exact trigonometric ratio of tan 5pi/12?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (eyust707):
well 5/12 = 3/12 + 2/12 right?
OpenStudy (anonymous):
..Yeah
OpenStudy (eyust707):
and
3/12 is 1/4
2/12 is 1/6
OpenStudy (anonymous):
Mhm
OpenStudy (anonymous):
I understand that far.. Kind of
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (eyust707):
sweet so that means that:
\[\tan ({5\pi \over 12} )= \tan ({3\pi \over 12} + {2\pi \over 12}) = \tan ({\pi \over 4} + {\pi \over 6})\]
OpenStudy (anonymous):
That makes sense so far, it's usually what follows that ends up looking like Chinese. >.<
OpenStudy (eyust707):
Well then you can use an identity...
OpenStudy (eyust707):
OpenStudy (eyust707):
the bottom one should work
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Do you mind showing me how it would work out?.. >.< Sorry
OpenStudy (eyust707):
No its fine =) as long as you help me
OpenStudy (eyust707):
what would you use for u?
OpenStudy (eyust707):
what about v?
OpenStudy (anonymous):
so u can be 1/4 and v can be 1/6
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (eyust707):
Yep! make sure you use (1/4)* pi\[\tan ({\pi \over 4} + {\pi \over 6})\]
OpenStudy (eyust707):
u = \(\pi \over 4\)
v = \(\pi \over 6\)
OpenStudy (eyust707):
we end up with|dw:1354678186124:dw|