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Mathematics 8 Online
OpenStudy (anonymous):

Which system has no solutions?

OpenStudy (anonymous):

A) x + y = -4 -3x + 2y = 2 B) x - 4y = -8 2x - 3y = -16 C) x - y = -2 3x - y = 0 D) x + y = -1 4x + 4y = -4 E) 4x + 6y = -12 2x + 3y = 9 & how do i determine whether it has no solution or not

OpenStudy (anonymous):

Look for the system where both equations have the same slope but different intercepts. That will represent parallel lines that do not intersect and thus have no solution. A quick way to see parallel lines is when the coefficients of "x" and "y" are in the same ratio. That way, you don't have to convert to slope-intercept form to see that two lines have the same slope.

OpenStudy (anonymous):

Extending that thought, 2 of the systems have lines where both are the slope. But only one of those 2 selections will have a different intercept.

OpenStudy (anonymous):

"the slope" is supposed to be "the same slope"

OpenStudy (anonymous):

If you aer not able to eyeball the equations to check for slope, then you have to convert all equations to the slope-intercept form y = mx + b. And then check the "m" values because "m" is your slope.

OpenStudy (anonymous):

Which system has infinite solutions? Which system has (1, 3) as the solution? Which system has (-2, -2) as the solution? Which system has (-8, 0) as the solution? these are the questions for the rest of them..

OpenStudy (anonymous):

so I need to put both equations in slope form?

OpenStudy (anonymous):

That's slope-intercept form. You have to do that if you can't do it visually or in your head. After a while, you would be able to do these in your head at a glance. That comes with a little practice and just doing enough of these. An infinity of solutions results from two equations written representing just one line. That means that one equation is a multiple of another. at this point, I would suggest putting all equations in the point-slope form.

OpenStudy (anonymous):

so let's say for a .. how would I put it in point-slope form? I know it's (y-y1)=m(x-x1)

OpenStudy (anonymous):

You don't want point-slope form, you want slope-intercept form which is: y = mx + b It is called that because the right-hand side has "m" for slope and "b" for the y-intercept. The very first equation can be put into slope-intercept form by subtracting "x" from each side.

OpenStudy (anonymous):

so the slope intercept form of a for both of the equations would be y = -x - 4 & y = 3/2x + 1 ?

OpenStudy (anonymous):

yes, very good.

OpenStudy (anonymous):

And since the system in "a" has equations of differing slopes, that system is intersecting lines and has one solution (one point), and that system is called "independent".

OpenStudy (anonymous):

So what question would that answer?

OpenStudy (anonymous):

Since we know that system ("a") has one solution, we can use either the elimination method or the substitution method to determine the point that satisfies both equations.

OpenStudy (anonymous):

Since you put both equations in the slope-intercept form, you have 2 equations that have "y =" or just "y" on the left. So, just set both right-sides equal to each other and solve for "x". Once you get "x", take either equation and put that value of "x" into the equation and get "y".

OpenStudy (anonymous):

x = -2

OpenStudy (anonymous):

& y also is -2 right?

OpenStudy (anonymous):

Okay, so basically i put the equations in slope int form, then solve for x and y. Thanks so much, you really did help :)

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