Can someone help me solve ln(x)-ln(x+1)=ln(x+3)-ln(x+5)
are you trying to solve for x?
I believe so. The instructions just say solve giving exact solution
properties of natural logs. ln(x(x+1)) = lnI(x+5)(x+3) go from there.
- means division
\[\ln(\frac{ x }{ x+1 }) = \ln(\frac{ x+3 }{ x+5 })\]
oh whoops sorry. i haven't done alg 2 in years!
yeah see that's what I thought it was too Veritas, but then there I got stuck
no problem. Yeah I'm trying to see how this would even help to solve the equation though.
take e of both sides to cancel out the ln's
no this is the natural log
Ignore that lat bit from me. :)
yeah I think Jenny's answer is the way to solve.
ok I'm gonna try and solve now
\[e(\ln (\frac{ x }{ x+1 }))=e(\ln(\frac{ x+3 }{ x+5 }))\]
and those e's should be raised to the power of the natural logs
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