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OpenStudy (anonymous):
Can someone help me solve ln(x)-ln(x+1)=ln(x+3)-ln(x+5)
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OpenStudy (anonymous):
are you trying to solve for x?
OpenStudy (anonymous):
I believe so. The instructions just say solve giving exact solution
OpenStudy (jennychan12):
properties of natural logs.
ln(x(x+1)) = lnI(x+5)(x+3)
go from there.
OpenStudy (anonymous):
- means division
OpenStudy (anonymous):
\[\ln(\frac{ x }{ x+1 }) = \ln(\frac{ x+3 }{ x+5 })\]
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OpenStudy (jennychan12):
oh whoops sorry. i haven't done alg 2 in years!
OpenStudy (anonymous):
yeah see that's what I thought it was too Veritas, but then there I got stuck
OpenStudy (anonymous):
no problem. Yeah I'm trying to see how this would even help to solve the equation though.
OpenStudy (jennychan12):
take e of both sides to cancel out the ln's
OpenStudy (anonymous):
no this is the natural log
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OpenStudy (anonymous):
Ignore that lat bit from me. :)
OpenStudy (anonymous):
yeah I think Jenny's answer is the way to solve.
OpenStudy (anonymous):
ok I'm gonna try and solve now
OpenStudy (anonymous):
\[e(\ln (\frac{ x }{ x+1 }))=e(\ln(\frac{ x+3 }{ x+5 }))\]
OpenStudy (anonymous):
and those e's should be raised to the power of the natural logs
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