Question

how do you solve Log5 (2-x) – 1 = log5 (2x-7)

Answer 1

is that log base 5?
if so just divide out the bases
so you get 2-x = 2x-7
solve for x

Answer 2

it is base five, but what about the minus 1?

Answer 3

move the logbase5(2x-7) to the other side and move the -1 over.
try from there?

Answer 4

i did and i got x=-3 and i feel like that's wrong

Answer 5

really? i got x = 3.

Answer 6

snap, lemme see

Answer 7

this is what i did.
-1=logbase5 (2x+7/2-x)
(2x+7)/(2-x)= 5^-1
(2x+7)/(2-x)=1/5
then i cross multiplied and got
5(2x+7)=1(2-x)
10x+35=2-x
11x+35=2
11x=-33
x=-3
righttttt?

Answer 8

Log5 (2-x) – 1 = log5 (2x-7)
i meant like move the -1 to the right and the logbase5(2x-7) to the left so you get
(2-x)/(2x-7) = 5
i got 3, but neither 3 nor -3 work as answers.
and your 2x+7 should be a -7...unless u wrote the question wrong...

Answer 9

nope, my question is from a worksheet. no error in my copying it down. but the negative one would be the exponent of the base 5, wouldn't it? so you'd have to raise five to the negative one?

Answer 10

i dunno why we're getting diff answers cuz u could do it multiple ways

Answer 11

struggles.