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Chemistry 19 Online
OpenStudy (anonymous):

If 3.95 g of N2H4 reacts and produces 0.750 L of N2, at 295 K and 1.00 atm, what is the percent yield of the reaction?

OpenStudy (anonymous):

Use PV=nRT to find the number of moles of N2 at the end. Convert 3.95g of N2H4 into moles. (moles of N2)/(moles of N2H4)*100% = percent yield

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