Question

R=log( I/Io) where Io is the intensity of a certain very small earthquake. What is the magnitude of an earthquake with intensity 8000 times Io?

Answer 1

I=8000I0
R=log(II0)
R=log(8000I0I0)
R=log(8000)
R=log(8)+log(103)
R=3+log(8)
R≈3.9

Answer 2

Oh I got the log(103) when I divided

Answer 3

just wondering... where exactly did the division occur.. did you replace the first I with the 8000? cause i dk what exactly the i0 is

Answer 4

yes

Answer 5

so what do i replace the Io with? should i replace it with 1?

Answer 6

Yea

Answer 7

oh ok, thank you!

Answer 8

wait, when you do the math where exactly did you get the result 103.. cause i can't figure out what you divided to get it.. extra slow in math here =/

Answer 9

It's hard to explain

Answer 10

my math is different from the teachers but I still get the same answer

Answer 11

i can see it is a bit different but in the line R=log(8000I0I0), do you divide log of 8000 * I o, and then divide it by I o or how does that change?

Answer 12

right you are doing it

Answer 13

so then the I o has to be a different number than 1 because 8000 *1 /1 = 8000 xD

Answer 14

well played yes

Answer 15

so what would that number be?

Answer 16

Idk never did it that way

Answer 17

so in that case how would you go about solving the problem?

Answer 18

Like how I did up there

Answer 19

what i'm asking is how did you get from R=log(8000I0I0) R=log(8000) to
R=log(8)+log(103)

Answer 20

division

Answer 21

lol what exactly did you divide O.O

Answer 22

R=log(8000I0I0) R=log(8000)

Answer 23

see those I marks those are getting rid of the zeros making it 8000

Answer 24

ooohhhh i see exactly what you mean! thanks man!

Answer 25

your welcome :D