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Chemistry 8 Online
OpenStudy (anonymous):

How many grams of C8H18 are needed to produce 100g CO2 in the following equation?

OpenStudy (anonymous):

OpenStudy (anonymous):

I have my work included in this.

OpenStudy (anonymous):

@Callisto @Preetha

OpenStudy (callisto):

Is the equation of the reaction given?

OpenStudy (anonymous):

oh yes, 2C8H18 + 25 O2 yields 16 CO2 + 18H2O

OpenStudy (anonymous):

Sorry, I forgot to include that part

OpenStudy (callisto):

Don't worry :) \[2C_8H_{18} + 25O_2 \rightarrow 16CO_2 +18H_2O\] no. of mole of CO2 produced required = 100/(12.0+16.0x2) = a No. of mole of C8H18 required = No. of mole of CO2 x (2/16) = a/8 = b Mass of C8H18 required = no. of mole of C8H18 required x (12.0x8 + 1.0x18) = b x (12.0x8 + 1.0x18) = answer you need. Is it clear?

OpenStudy (anonymous):

That seems generally what I did

OpenStudy (anonymous):

Thanks Callisto, that was the same result I got!

OpenStudy (callisto):

You're welcome. :)

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