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Algebra 9 Online
OpenStudy (anonymous):

f(x)=160+10 log x

OpenStudy (hunus):

What do you need help with?

OpenStudy (anonymous):

solving. sound levels in decibels can be computed by f(x)=160+10 log x, where x is the intensity of the sound in watts per square centimeter. The intensity of a sound is 10^-6 watts per square centimeter. How many decibels does this quantity represent?

OpenStudy (hunus):

"sound levels in decibels can be computed by f(x)=160+10 log x" This tells us that the function f(x) here is the sounds level in decibels "x is the intensity of the sound in watts per square centimeter" and this tells us that the sound level is a function of the intensity of the sound So inputting the given value of intensity for x (10^-6) What do you get?

OpenStudy (anonymous):

is the answer 100?

OpenStudy (hunus):

Not quite, when we input 10^-6 into the equation we get \[f(10^{-6})=160 + 10\log(10^{-6})\] Try plugging that into your calculator

OpenStudy (anonymous):

I Got 100.

OpenStudy (hunus):

ahhh, my mistake. Sorry. Yes, you're correct :)

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