Question

Solve the system:3x-2y= 10
-6x+5y= -2
write your answer as an ordered pair (x,y). leave answers in fraction form if needed

Answer 1

(equation one)\[=3x-2y =10\]
\[2(3x-2y)=2(10)\]
\[6x-4y=2\]
*all i did was multiply both sides by 2 to get 6x in the equation to cancel when adding equation one and two together

(equation two)
\[-6x+5y=-2)\]

ADD BOTH EQUATIONS(add left sides up and right sides up)

\[6x-4y+(-6x+5y)=20+(-2)\]
\[6x-4y-6x+5y=20-2\]
\[6x-6x+5y-4y=18\]
\[(6-6)x+(5-4)y=18\]
\[0x+y=18\]
\[y=18\]

take your y answer and put it into one of the equations you added together

\[-6x+5y=-2\]
\[-6x+5(18)=-2\]
\[-6x=-92\]
\[x=\frac{-92}{-6}=\frac{92}{6}\]

Answer 2

can you simplify 6/92?

Answer 3

\[\frac{92}{6}=\frac{2}{2}*\frac{46}{3}\]

Answer 4

\[=1*\frac{46}{3}\]

Answer 5

thank you!

Answer 6

btw @Trplingup i think you forgot to divide the right side when you divided by two... but you deleted before i could check =/

Answer 7

Yea I did I deleted since it was wrong too bad you can't edit