An electron moves 0.05 m in the direction of an electric field of strength 200N/C. Remember that charge on an electron is 1.6 x 10^-19 C. What is the change in electrical potential energy of the electron

Question

vincent-lyon.fr · Answer

Charge of an electron is    $q=-e=-1.6\times 10^{-19} \,\text C $

anonymous · Answer

multiply 200N/C by 0.05 m and you should get electric potential difference.
the formula i think is Voltage=epsilon times radius.

vincent-lyon.fr · Answer

Change in potential is   ΔV = E.d
Change in electric potential energy is ΔPE = q.ΔV