Inverse trig function: -5cot^-1 [x/6] find dy/dx. I have alot of problems like this and I need help with one so I can do the rest

Question

Inverse trig function: -5cot^-1 [x/6] find dy/dx.    I have alot of problems like this and I need help with one so I can do the rest

anonymous · Answer

The formula for the derivative of the inverse cotangent is $$\frac{ d }{dx}(arccot)x = -\frac{ 1 }{ 1 + x^2 }$$
For this problem after you take the derivative should look something like this after applying chain rule and prior to simplification$$-5[-\frac{ 1 }{ 1 + (\frac{ x }{ 6})^2}]\frac{ 1 }{ 6}$$
After some cleaning up would look like $$\frac{ 5 }{ 6 }(1 + (\frac{ x }{ 6 })^2)^{-1}$$

anonymous · Answer

Is that the final answer?

anonymous · Answer

If you are taking d/dx.  Is this for calc 1?

anonymous · Answer

Since this is already solved for y, dy/dx is in essence the same as d/dx.  And is the final although could choose other ways to simplify.