Question

Inverse trig function: -5cot^-1 [x/6] find dy/dx. I have alot of problems like this and I need help with one so I can do the rest

Answer 1

The formula for the derivative of the inverse cotangent is \[\frac{ d }{dx}(arccot)x = -\frac{ 1 }{ 1 + x^2 }\]
For this problem after you take the derivative should look something like this after applying chain rule and prior to simplification\[-5[-\frac{ 1 }{ 1 + (\frac{ x }{ 6})^2}]\frac{ 1 }{ 6}\]
After some cleaning up would look like \[\frac{ 5 }{ 6 }(1 + (\frac{ x }{ 6 })^2)^{-1}\]

Answer 2

Is that the final answer?

Answer 3

If you are taking d/dx. Is this for calc 1?

Answer 4

Since this is already solved for y, dy/dx is in essence the same as d/dx. And is the final although could choose other ways to simplify.