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Physics 12 Online
OpenStudy (ksaimouli):

help

OpenStudy (ksaimouli):

the mass of an automobile is 1160 kg, and the distance between its front and rear axles is 2.54m. The center of gravity of the car is between the front and rear tires, and the horizontal distance between the center of gravity and the front axle is 1.02 m. Determine the normal force that the ground applies to (A) each of the two front wheels an to (B) each of the two rear wheels.

OpenStudy (ksaimouli):

interesting one

OpenStudy (anonymous):

idk :O

OpenStudy (cj7529):

|dw:1354750892209:dw| Weight of the car W = mg = 1160 x 9.81 =11379.6N effectively you have a torque or moment problem now: |dw:1354751216998:dw| So, Force x distance = torque F1x(2.54-1.02)=F2x1.02 and because the upwards force balances the downwards force: F1 +F2 = W Now you have 2 equations for F1 and F2 and you can solve them simultaneously you ok from here????? =)

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