Question

Fraction question

I have 69/h and I was to isolate h, will it matter if i multiply or divide by 69 to isolate h?

Answer 1

Your problem is 69/h...? There is nothing else in the problem?
Because I don't see how you're suppose to isolate h if we can't manipulate the other side of the equation D: hmm

Answer 2

its a word problem and i have the half life equation and i'm trying to find the half life which is h, so far i have log1/square root 2/log 1/2 =69/h

Answer 3

I can't understand with the way you wrote that...
Is this what it looks like?\[\huge \frac{\log\left(\frac{1}{\sqrt2}\right)}{\log\left(\frac{1}{2}\right)}=\frac{69}{h}\]

Answer 4

yes

Answer 5

Ummm the way I would do this, might be a little confusing. It might be easier if you remember how to do Cross Multiplication.

Answer 6

Anyway this is how I would do it :D maybe it'll make sense.
Start by multiplying both sides by h.\[\huge h\cdot \frac{\log\left(\frac{1}{\sqrt2}\right)}{\log\left(\frac{1}{2}\right)}=\frac{69}{h}\cdot h\]The h's on the right will cancel out, giving us,\[\huge h\cdot \frac{\log\left(\frac{1}{\sqrt2}\right)}{\log\left(\frac{1}{2}\right)}=69\]Then to get rid of that big fraction, multiply both sides by it's reciprocal (the same fraction but FLIPPED).\[\huge h=69\frac{\log\left(\frac{1}{2}\right)}{\log\left(\frac{1}{\sqrt2}\right)}\]
It's just a matter of moving things around to isolate h.
If that was rather confusing, think back to cross multiplication :D

Answer 7

what if h was on top, so h/69, will it still be the same result, because thats the way i'm thinking of it, but im multiplying both sides by the reciprocal or fraction to isolate h

Answer 8

if h was on top, we would have a lot less work, we only have to move the 69 to the other side.

So we would have ended up multiplying both sides by 69, and that's all.

Answer 9

ok, thanks