Question

simplify (x^-3y^5z^0/x^2y^8)^2

Answer 1

\[\frac{ x^-3y^5z^0 }{ x^2y^8 }^2\]

Answer 2

()^2

Answer 3

\[(x ^{-3}y ^{5}z ^{0}/x ^{2}y ^{8})^{2}\]

simplify it by dividing term by term
like
x^-3/x^2 =x^-3-2=?

y^5/y^3=y^5-3=?

also what is z^0=?

Answer 4

x^6

Answer 5

y^-15

Answer 6

\[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]

Answer 7

\[\left(\begin{matrix}x^-3y^5z^0 \\ x^2y^8\end{matrix}\right)^2\]

Answer 8

thats the problem

Answer 9

i'm new at this

Answer 10

yeah later on you squared them after simplifying the terms

Answer 11

oh

Answer 12

i'm so lost with these

Answer 13

but first simlipfying the division of powers are adding and subtracting on not multiplying .. :D

Answer 14

so x^1y^-3z^0

Answer 15

\[\frac{ z }{ x^2y^6 }\]

Answer 16

\[\frac{ y ^{-c} }{ y ^{b} }=y ^{-c-b}\]

Answer 17

look i dont understand

Answer 18

\[\frac{ v ^{-c} }{ y ^{b} }=y ^{-c}*y ^{-b}=y ^{-c-b}\]

Answer 19

i get the x^-1*2 y^-3*2

Answer 20

for example only

\[\frac{ y ^{-5} }{ y ^{7} }=y ^{-5}*y ^{-7}=y ^{-5-7}=y ^{-12}\]

Answer 21

oh

Answer 22

when you move the denominator to the numerator the sign of its power is change

Answer 23

ok

Answer 24

\[\left(\begin{matrix}x^0 \\ x^1y^3\end{matrix}\right)^2\]

Answer 25

thats what i got

Answer 26

\[\left(\begin{matrix}z \\ x^1y^3\end{matrix}\right)^2\]

Answer 27

that top is z

Answer 28

hm the idea is to move all the denominator upward to the numerator first then do add or subtract

Answer 29

so x^-3-2y^5-8z^0

Answer 30

yes correct and z^0=1 right?

Answer 31

i guess

Answer 32

so x^-1y-3z^1

Answer 33

any number or letter raised to the power of zero is =1

Answer 34

oh right i have been working on homework for the last 5 hours my mind is fried =)

Answer 35

hmm what is

-2-3=?
5-8=?

Answer 36

your 5-8= -3 is correct :D

Answer 37

-5

Answer 38

yesss :D

Answer 39

yess =)

Answer 40

so whats the answer now?

Answer 41

so x^-5y^-3x^1

Answer 42

than that times 2

Answer 43

so x^-5*2=-10 y^-3*2=-6 x^1*2=2

Answer 44

\[\left(\begin{matrix}z^2 \\ x^10y^6\end{matrix}\right)\]

Answer 45

now that z^0=1
\[(x ^{-5}y ^{-3})^{2}=\]?

Answer 46

x^-10y^-6

Answer 47

\[(x ^{b})^{a}=x ^{ab}\]

multiply now the power here

Answer 48

x^-5*2

Answer 49

=10

Answer 50

yess correct do that to y also

Answer 51

y^-3*2=-6

Answer 52

yess but dont forget about the sign :D

Answer 53

so it's z^2/x^10y^6

Answer 54

hmm z is not supposed to be there any more since its value is 1 anything you multiply by 1 is itself like
ax1=a

Answer 55

oh so it's 1/x^10y^6

Answer 56

yesssssssssssss :D

Answer 57

its right!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 58

thanks

Answer 59

YW have fun now and enjoy solving good luck ......... :D

Answer 60

would u mind helping me with the other one i have on line

Answer 61

ok yesss where is it? @hannalafave

Answer 62

it did not work but i got one for u now 12a^3-3a^2-5a+10/4a+3

Answer 63

ok the easy one to do for this one is by long division can you try that?

Answer 64

yea can u go to link i sent u?

Answer 65

ok