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OpenStudy (anonymous):
Find the volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm.
A. 11,520 cm3
B. 23,040 cm3
C. 7,680 cm3
D. 768 cm3
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OpenStudy (anonymous):
1/3(48)^2(26)=416.......?
OpenStudy (anonymous):
V=1/3(l^2)(h)
OpenStudy (anonymous):
@Phydeaux would u happen to know this , i have the form but dnt know y its not comming out right
OpenStudy (anonymous):
l=48
h=26
OpenStudy (anonymous):
Sooo V= ((48^2)(26))/3
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OpenStudy (anonymous):
Hmm. I get 19,968. Give me a sec.
OpenStudy (anonymous):
wut does pl mean again
OpenStudy (anonymous):
found my mistake.... I was using slant height rather than actual height. One sec.
OpenStudy (anonymous):
I got C. The height is 10,
so ((48^2)(10))/3=V
OpenStudy (anonymous):
thank u ya i was using 26
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OpenStudy (anonymous):
You have to use pythagorean theorem to calculate the height rather than slant height, and use regular height. You're welcome. :]
OpenStudy (anonymous):
|dw:1354756959126:dw| sorry I meant the height to be 10 in my drawing, but here it is!!!
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