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Mathematics 19 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

okay....first you have to move everything to one side..move the 14x +20 to the left.

OpenStudy (anonymous):

pull the x out 2x2=14x+20 4=14x+20 0=14x+16 x(14+16) x(30) 30x

OpenStudy (anonymous):

so first, you have to make it in proper form, which is 2(x^2+7x-10) now do you see it?

OpenStudy (anonymous):

(x+2)(x-5)

OpenStudy (anonymous):

Because 5 times 2=10, and 5+2 equals 7. You just needed to rewrite your equation so it looks easier.

OpenStudy (anonymous):

so the final answer is (x+2)(x-5)

OpenStudy (anonymous):

oh i think you are going to have to do the quadratic equation

OpenStudy (candyme):

Okay, so when you move them over you will get \[2x^2-14x-20\] This doesn't factor, so you need to use the quadratic formula or completing the square. I'm going to do completing the square. \[x^2-7x-10\]\[x^2-7x+... =10+...\]\[x^2-7x+\frac{ 49 }{ 4 }=10+\frac{49}{4}\]Factor/Add to Simplify\[(x-\frac{7}{2})^2=\frac{89}{4}\] Take the Square Root of Both Sides\[ \sqrt{(x-\frac{7}{2})^2}=\pm \frac{\sqrt{89}}{\sqrt{4}}\]\[x-\frac{7}{2}= \pm \frac{\sqrt{89}}{2}\]\[x=\frac{7}{2} \pm \frac{\sqrt{89}}{2}\] OR \[x=\frac{7\pm \sqrt{89}}{2} \]

OpenStudy (candyme):

That look right?

OpenStudy (candyme):

You're welcome! Glad I could help, let me know if you need anything else.

OpenStudy (candyme):

\[x=-3 \pm \sqrt{2}\]You are correct

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