A 0.25 Kg hockey puck is hit with a force of 7.00 N. The force of friction acting on the puck when it is hit is 0.30 N. What is the magnitude of the acceleration of the hockey puck?

A 12.7 m/s2
B 28.0 m/s2
C 26.8 m/s2
D 29.2 m/s2

Question

A 0.25 Kg hockey puck is hit with a force of 7.00 N.  The force of friction acting on the puck when it is hit is 0.30 N. What is the magnitude of the acceleration of the hockey puck?

A	12.7 m/s2
B	28.0 m/s2
C	26.8 m/s2
D	29.2 m/s2

anonymous · Answer

C is the answer. just find the net force by subtracting 7-0.3 and dividing by acceleration

anonymous · Answer

i dont understand what it means by magnitude of acceleration

anonymous · Answer

it just means size

anonymous · Answer

what would the acceleration be in this case? would be have to solve for it?

anonymous · Answer

F net= massxacceleration

anonymous · Answer

$$F _{1}-F _{2}=ma$$ you solve for a by dividing by the mass.
F1 is 7 and F2 is .3

anonymous · Answer

force - friction = mass x acceleration
7.0N - 0.3N= 0.25 x a
6.7/0.25 = a
a=26.8m/s2

anonymous · Answer

This is simply an instantaneous acceleration for the puck at this given moment in time.

anonymous · Answer

thanks yall! sorry i wish i couldve given you all the best answer!

anonymous · Answer

i just noticed the typo in my first post, its divide by mass

anonymous · Answer

yeah thats why i was confused @qvbsinteta haha

anonymous · Answer

F=ma magnitude of the acceleration just means that the acceleration is in the direction of the applied force and it cannot be zero (0). so just  keep in mind that magnitude is the same as the size.