The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right. The cage has a potential energy of 705,600 J when it is at the top of the drop. Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s?

A 51 m
B 8.6 m
C 60 m
D 45 m

Question

The 1200 Kg open cage of a tower drop amusement park ride is shown in the picture to the right.  The cage has a potential energy of 705,600 J when it is at the top of the drop.  Ignoring friction, at what height during the cage drop would the cage have a velocity of 13 m/s?

A	51 m
B	8.6 m
C	60 m
D	45 m

anonymous · Answer

best answer could be 8.6m

anonymous · Answer

what formula did u use?

anonymous · Answer

use conservation of energy and solve for 
mgh=0.5mv^2; expression is 
h= v^2/(2g)

anonymous · Answer

so u dont need to use the mass at all?

anonymous · Answer

the masses cancel out eventually..

anonymous · Answer

how so?

anonymous · Answer

in all cases when dealing with energy, and asking for the height, or in this one specifically?

anonymous · Answer

mgh=0.5mv^2

it is a general expression for the height when u r using the principle of conservation of energy. potential energy equals change in kinetic energy. therefore we get an equation for the height h= V^2/ 2g

anonymous · Answer

oh so it would most probably always cross out! ahh thank you!

anonymous · Answer

yup.. :) u welcome