differentials help! Volume of a cube = s^3, s=10, ds=0.1 i need to find the estimated dV and the actual ΔV. i dont know what it means.
\[V=s ^{3}\]\[dV=3s ^{2}\times(ds)\] Solve for ds by plugging in other values, so set ds on one side and the other variables on the other side: \[dV/(3s ^{2}) = ds\]
V = Volume fo the Cube s = measure of one edge of the cube, \(V(s) = s^{3}\) \(\dfrac{dV}{ds} = 3s^{2}\) or \(dV = 3s^{2}\cdot ds\) Are we getting anywhere? The notation may be new.
I'm pretty sure I have never seen ds=.1, since that doesn't make a whole lot of sense.
idk.. this is the problem my teacher gave me.
ds means change in side length per time.
No, ds doesn't mean that, ds/dt means that.
ok soo dV = 3s^2ds now how do i find ΔV? what does that even mean?
Change in volume.
wait is dV and ΔV the same thing?
I've done calculus for about 2 years and I have never seen a problem like this, simply because it is nonsensical.
ds is an infinitesimal, not a real number, plain and simple. It would be like saying infinity=90billion, solve.
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