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Mathematics 14 Online
OpenStudy (anonymous):

Help Please-Find the rank of this matrix: 2 1 3 1 -1 2 1 0 3

OpenStudy (anonymous):

just do elimination

OpenStudy (anonymous):

whatever they call it

OpenStudy (anonymous):

do you know the form x+y+z 0+y+z 0+0+z

OpenStudy (anonymous):

gaussian elimination

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

just work it like that :/

OpenStudy (anonymous):

But how do you know it's rank?

OpenStudy (anonymous):

The rank of a matrix is the maximum number of independent rows (or, the maximum number of independent columns). http://chortle.ccsu.edu/vectorlessons/vmch16/vmch16_15.html :P

OpenStudy (anonymous):

ok, thanks. And how do you know the basis for the row space of a matrix. This is confusing :(

OpenStudy (anonymous):

sorry looking :/

OpenStudy (anonymous):

np

OpenStudy (nubeer):

the number of non zero rows or column is rank #

OpenStudy (anonymous):

okies once got your constant it is the dependent this is why it is becomes the basis of you calculations example 1 2 3 0 4 6 0 0 7 7 is your dependent variable because you are doing all this work ( and i am also, typing) (i know i am repeating myself ) doing all this work to arrive the number 7 you will be using this to solve this your equation without it you cannot go on you depend on it it will be the BASIS

OpenStudy (nubeer):

|dw:1354781712049:dw|

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