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if tany(1+tanx)=1-tanx,show that dy\dx=-1
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Let,, tanx =t,, then tany (1+t)=1-t
then
|dw:1354847389778:dw|
now what will be the next steps?
\[y=\tan^{-1}[ (1-t)/(1+t)]\]
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Now do dy/dx
at the last substitute t=tanx
without substitution we can solve this
we can it is laborious.. usually people solve this type by substituting
|dw:1354848032336:dw|
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ya its possible
substitute sec x by (1/cosx) and tanx by (sinx/cosx) and chk
plz let me know how?
CHK
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thanks raja!
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