Question

can someone help me with an equilibrium expression

Answer 1

\[for the reaction H20 - cl2 \rightarrow \leftarrow 2HCL K _{c} = 2.13 x10^{29} at \hat temperature of 341K. What is K _{p} at this temperature?\]

Answer 2

Kp=Kc(RT)^delta(n)

n=coefficient on products-coefficients of reactants

Answer 3

would the coefficient for the reactances be 2?

Answer 4

according to the reaction you wrote:
1H2O + 1CL2 <-> 2HCL

2-(1+1)=0

so (RT)^0=1, so Kp=Kc

Answer 5

yea, thank you

Answer 6

no problem